From clocks that mark the passage of time, to the metronome that sets pace to our
instruments, objects that perform periodic motion are all around us. It is essential,
therefore, to explore the mechanics of periodic motion and understand the physics and
mathematics that govern various oscillating systems.
Author: Sammith S, Editor: Iris Litiu
1. Article overview
This article explores the most basic form of periodic motion known as simple harmonic
motion(SHM).We will go over the characteristics of simple harmonic oscillators and
study idealized physical systems to derive the equations for the motion of these oscillators.
2. Characteristics of simple harmonic oscillators
A great example for a simple harmonic oscillator is the pendulum which is illustrated
below. Point A is the equilibrium position for the pendulum. When we draw the bob
of the pendulum away from its equilibrium position to point C and release it, we see
that the bob overshoots the equilibrium position and stops momentarily at point B (the
extreme of its motion), before swinging back towards the equilibrium and reaching its
initial position (Point C). In a nutshell, the motion of the pendulum is due to the gravitational force (the restoring force) attracting the bob towards the equilibrium position
and the inertia of motion causing the bob to overshoot and reach the other extreme of
its motion.
The figure also highlights the breakdown of mechanical energy of the bob. When the
bob is brought to point C where the vertical displacement is the highest, the bob has
maximum gravitational potential energy and no kinetic energy. When it passes through
the equilibrium position, the vertical displacement is zero and the bob has no gravitational potential energy but has maximum kinetic energy. So, the velocity is maximum
at the equilibrium position.
The above physical characteristics of the pendulum are common to all simple
harmonic oscillators:
Periodic motion
Restoring force (gravitational force in the case of a pendulum)
Inertia of motion causing the oscillating particle to overshoot the equilibrium position
Constant flow between kinetic and potential energy
3. Idealized oscillating systems
We generally utilize idealized physical systems as real physical systems tend to be
complicated and contain a number of factors. We begin with an idealized system and
then add the necessary variables to obtain the best solution to the problem at hand.
3.1 Mass attached to a horizontal spring
The first oscillating system that we consider is a mass attached to a horizontal spring.
Here the force of gravitation is negated by the normal force and hence, there is no
displacement in the y direction. This system is idealized as we assume that the
surface is frictionless and the mass of the spring is negligible.
The equilibrium position for this system is where the spring is un-stretched which is
marked as 0.x is defined as the displacement of the mass from the equilibrium
position. When the spring is extended, i.e., is positive, the restoring force acts in the
opposite direction to x to pull the mass back to the equilibrium position. When the
spring is compressed, i.e., x is negative, the restoring force acts in the opposite
direction of x to push the mass back to the equilibrium position.
The force produced by the spring can be described by Hooke’s law. The Hooke’s
law gives us the strength of the restoring force which is proportional to the extension
or compression of the spring (which is x).This can be written as F ∝ x.
The constant of proportionality becomes the spring constant k which is defined as the
force per unit displacement and the equation for the restoring force becomes
The negative sign indicates that the force always acts in the direction opposite to the
displacement. However, this system must obey Newton’s first law of motion which means that
Acceleration is a measure of the rate of change in velocity. Velocity, which is
v(t)=dx/dt, is the rate of change of position with respect to time. So this means that
acceleration is the derivative of a derivative: the second derivative with respect to
position, or the derivative of velocity. Now that we know acceleration is the second
time derivative of position,
By substituting equation 3 in equation 2, we get,
Further simplification lets us write the equation as,
By assuming that,
We can write,
w^2 is basically the restoring force per unit displacement per mass. The usage ofw2
instead of w is to make the calculations simpler and it will become evident as we
explore more of SHM. The equation that we have obtained is the equation of SHM
and all simple harmonic oscillators have an equation of this form.
4.2 Mass on a vertical spring
Another system that we consider is a mass attached to a vertical spring and the
setup is shown below.
In this system, we have the gravitational force acting on the mass. When you initially
attach the mass to the spring, we see that the length of the spring extends by ∆l.
To find out the resultant force on the mass, we need to subtract the force exerted
upwards by the spring from the gravitational force (we assume that displacements in
the downward direction are positive).Hence, the resultant force on the mass is given
by,
The above equation can also be written as mg = k∆l. The resultant force acting on
the mass is given by F = mg−k(∆l+x) and subsequent expansion of the equation
gives rise to F = mg−k∆l−kx. But we already know that mg = k∆l, which gives
rise to,
This is identical to the one obtained when we derived the equation of motion for a
mass attached to a horizontal spring.
Now let us try to derive the equations for displacement, velocity and acceleration for a
simple harmonic oscillator. When we plot the motion of any simple harmonic
oscillator, we get a plot that resembles the cosine function.
Figure 5 plots the displacement x of the mass with respect to time t. The maximum
displacement of the mass is known as the amplitude (A) and we can see the amplitude
at t=0.The time it takes for the mass to complete one cycle of oscillation is called
period (T). Frequency gives us the number of cycles of oscillations that happen per
unit time and is denoted by v. The relationship between period and frequency is given
by,
The units of frequency are Hertz where 1 Hertz is equivalent to 1 cycle per second.
When we consider figure 5, we see that the 2πt/T is the angle covered from 0 to 2π as t
goes from 0 to T. Hence, we can express displacement as,
Next, we define the angular frequency as,
By substituting equation 11 in equation 10, we get,
It is now simple to obtain the velocity and acceleration. Keeping in mind that,
and that,
By taking the first time derivative of x, we get velocity as,
And by taking the second time derivative of x, we obtain the acceleration as,
We can see that equation 7 equals equation 11 and the reason for writing w^2, which is
the square of the angular frequency, becomes evident. We have also derived the
equations for displacement, velocity and acceleration when x = A. The graphs for the
derived equations are illustrated below.
The aligned time axes makes it easier for us to examine figure 6. When x is at the
highest (i.e., at A), we see that the velocity is 0. We also see that the velocity is
maximum when the mass is at its equilibrium position.
Comments